..... ⇔ x³(x² - 2) = 0  ⇔  x³(x + √2)(x - √2) = 0  ⇔ x  = 0 lub x = √2  lub x = -√2

[latex]x^{5}-2x^{3} = 0\\x^{3}(x^{2}-2) = 0\\x^{3}(x + sqrt{2})(x-sqrt{2}) = 0\\x^{3} = 0 vee x+sqrt{2} = 0 vee x-sqrt{2} = 0\\x = 0 vee x = -sqrt{2} vee x = sqrt{2}\\x inlbrace-sqrt{2};0;sqrt{2} brace[/latex]